3[3x-4(y-3)]=

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Solution for 3[3x-4(y-3)]= equation:


Simplifying
3[3x + -4(y + -3)] = 0

Reorder the terms:
3[3x + -4(-3 + y)] = 0
3[3x + (-3 * -4 + y * -4)] = 0
3[3x + (12 + -4y)] = 0

Reorder the terms:
3[12 + 3x + -4y] = 0
[12 * 3 + 3x * 3 + -4y * 3] = 0
[36 + 9x + -12y] = 0

Solving
36 + 9x + -12y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-36' to each side of the equation.
36 + 9x + -36 + -12y = 0 + -36

Reorder the terms:
36 + -36 + 9x + -12y = 0 + -36

Combine like terms: 36 + -36 = 0
0 + 9x + -12y = 0 + -36
9x + -12y = 0 + -36

Combine like terms: 0 + -36 = -36
9x + -12y = -36

Add '12y' to each side of the equation.
9x + -12y + 12y = -36 + 12y

Combine like terms: -12y + 12y = 0
9x + 0 = -36 + 12y
9x = -36 + 12y

Divide each side by '9'.
x = -4 + 1.333333333y

Simplifying
x = -4 + 1.333333333y

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